C++ FAQ Celebrating Twenty-One Years of the C++ FAQ!!!
(Click here for a personal note from Marshall Cline.)
Section 33:
[33.10] Can I convert a pointer-to-member-function to a void*?

No!

class Fred {
public:
  int f(char x, float y);
  int g(char x, float y);
  int h(char x, float y);
  int i(char x, float y);
  ...
};

// FredMemFn points to a member of Fred that takes (char,float)
typedef  int (Fred::*FredMemFn)(char x, float y);

#define CALL_MEMBER_FN(object,ptrToMember)  ((object).*(ptrToMember))

int callit(Fred& o, FredMemFn p, char x, float y)
{
  return CALL_MEMBER_FN(o,p)(x, y);
}

int main()
{
  FredMemFn p = &Fred::f;
  void* p2 = (void*)p;                  //  illegal!!
  Fred o;
  callit(o, p, 'x', 3.14f);             // okay
  callit(o, FredMemFn(p2), 'x', 3.14f); // might fail!!
  ...
}
Technical details: pointers to member functions and pointers to data are not necessarily represented in the same way. A pointer to a member function might be a data structure rather than a single pointer. Think about it: if it's pointing at a virtual function, it might not actually be pointing at a statically resolvable pile of code, so it might not even be a normal address — it might be a different data structure of some sort.

Please do not email me if the above seems to work on your particular version of your particular compiler on your particular operating system. I don't care. It's illegal, period.